= Solution
The pointer argument must be passed by reference, because it is replaced:
``
procedure Lengthen(var n: number)
old := n
L := len(old)
new(result, 2*L)
for i := 0 to L-1 do
result[i] := old[i]
for i := L to 2*L-1 do
result[i] := 0
n := result
``
The low-order coefficients are preserved and the newly allocated high-order coefficients are zero, so the <digit-array integer representation> has the same value. The allocation remains nonempty because $L\geq1$. Neither allocation nor an uninitialized high-order cell may be assumed to contain zero. Any other reference to the old array still denotes that old array; the code does not free storage through an alias.
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