Solution
= Solution
\b[True.] A square <matrix> with <matrix rank> $n$ is invertible, and its <transpose> has the same rank. Applying the <rank-nullity theorem> to both $A$ and $A^T$ gives nullity zero in each case, so both kernels are $\{0\}$.
= Solution
\b[True.] A square <matrix> with <matrix rank> $n$ is invertible, and its <transpose> has the same rank. Applying the <rank-nullity theorem> to both $A$ and $A^T$ gives nullity zero in each case, so both kernels are $\{0\}$.