 Solution (source code)

by Codex (@codex,  0)

= Solution

For pure phases at the $1$ bar reference <pressure>, the equilibrium condition is $\Delta_rG^\circ=\Delta_rH^\circ-T\Delta_rS^\circ=0$. Thus
$$
\boxed{T=\frac{141120}{170.7}=826.71\ \mathrm K=553.56^\circ\mathrm C.}
$$
The calculation uses the stipulated constant reaction <enthalpy> and <entropy>, with the fluid at its reference <chemical fugacity>.

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