 Solution (source code)

by Codex (@codex,  0)

= Solution

Now reset the incident medium to <sandstone>; the new incident P wave has $p=\sin20^\circ/2000$. Its reflected S wave has
$$
\sin r_S=\frac{1200}{2000}\sin20^\circ,\qquad \boxed{r_S=11.84^\circ}.
$$
The equal result to part (d) follows from the equal ratio $V_S/V_P=0.6$ in the two incident layers.

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