Solution (source code)

= Solution

Sixteen hours is $2/3$ of a day, so the <sampling rate> is
$$
\boxed{f_s=\frac1{16\,\mathrm h}=1.5\,\mathrm{day^{-1}}
\simeq1.7361\times10^{-5}\,\mathrm{Hz}.}
$$