Solution
= Solution
At the one-bar <standard state>, pure phases have unit <thermodynamic activities>. The <Gibbs energy of reaction> balance is $\Delta_rH^\circ-T\Delta_rS^\circ=0$, giving
$$
\boxed{T=\frac{141120}{170.7}=826.714\,\mathrm K\simeq553.564\,{}^\circ\mathrm C.}
$$
This uses the stipulated temperature-independent reaction <enthalpy> and <entropy> differences, taken per mole of the written reaction.