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Put $a={\lambda }_P$ and $b={\lambda }_Q$. The Pauli operators are Hermitian and satisfy $P^2=Q^2=I$ and $PQ+QP=0$, soThus $V$ is a unitary operator. For every Pauli operator $R$, according as $R$ commutes or anticommutes with $P$ and $Q$, expansion of $VRV$ gives one of $\pm R$ or $\pm RPQ$, up to the phase that makes it Hermitian. It is therefore another Pauli operator, so $V$ normalizes the Pauli group and is a Clifford operation. Finally,which is the normalized projection onto the eigenvalue-$b$ eigenspace of $Q$. Hence $V$ maps the eigenvalue-${\lambda }_P$ eigenspace of $P$ onto the eigenvalue-${\lambda }_Q$ eigenspace of $Q$.

Since $P|\psi ⟩={\lambda }_P|\psi ⟩$, $P^2=I$, and $P$ anticommutes with $Q$,so the expectation value of $Q$ is zero. The two spectral projectors of the Hermitian Pauli operator $Q$ are $(I\pm Q)/2$, and hence the Born rule gives

Propagate each output observable backwards through the Clifford circuit and writeThe $Q_i$ are mutually commuting Pauli operators, and measuring them on $|0{⟩}^{\otimes n}\otimes |\varphi ⟩$ has exactly the required joint output distribution. Initially the first $n$ qubits are constrained by the stabilizer generators $Z_1,\dots ,Z_n$. Process the $Q_i$ in order. If $Q_i$ anticommutes with a current generator, part b gives a uniform outcome and a Clifford operation that replaces that generator by $Q_i$; this step needs no measurement on $|\varphi ⟩$. If $Q_i$ commutes with every current generator, multiply it by known generators to remove its action on the first register. What remains is a Pauli observable $P_j$ on the $t$ resource qubits and is measured there. The nontrivial $P_j$ are independent and mutually commuting. An independent commuting family of Pauli operators on $t$ qubits has at most $t$ members, so $s\le t$. All effective observables are fixed by the original commuting family; the sampled outcomes merely update the classical Clifford frame. The resulting nonadaptive Pauli-based computation, followed by the stated $Z_1,\dots ,Z_n$ outputs, is therefore a weak classical simulation of a quantum circuit with the same joint distribution.

An $n$-qubit stabilizer state is the unique simultaneous $+1$ eigenstate of an abelian group $G$ of Pauli operators having $2^n$ elements and not containing $-I$. The group $G$ is the state's stabilizer group; equivalently, it is generated by $n$ independent commuting Hermitian Pauli operators.

Let $A=X\otimes X\otimes I$ and $B=Z\otimes I\otimes Z$. The two Pauli operators anticommute because their local factors anticommute at exactly one qubit. Since $A^2=B^2=I$, the mixed terms cancel andThis is a scalar, or $0$-local, Hamiltonian, so the smallest value is $\boxed{k=0}$.

A strong classical simulation of a quantum circuit computes any requested output probabilityin polynomial time, to the prescribed inverse-polynomial accuracy. A weak classical simulation of a quantum circuit instead produces classical samples from the circuit's output distribution, with exact or suitably small total-variation error.

The Extended Gottesman--Knill theorem states that a unitary Clifford circuit with an arbitrary product state input and final computational-basis measurements is weakly classically simulable. It is strongly simulable when only $O(\log n)$ output qubits are measured. Indeed, each joint output projector expands into $2^k$ Pauli operators, and Clifford conjugation maps every such operator to another Pauli operator whose expectation factors over the input qubits. The factor $2^k$ is polynomial precisely for $k=O(\log n)$.

A set of stabilizer generators is an independent commuting family of Hermitian Pauli operators whose products form a stabilizer group.