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 Incoming links: Power maps of a reciprocal-coordinate hyperbola

Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2021 / Paper 1 / 11 / c / Solution 2026-10-18
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From X=s2−4 and Y=4s, elimination of s gives
Rev=16(Imv)2​−4,−15≤Imv≤15.​
(1)
This makes the real part a quadratic function of the imaginary part. There is no sign ambiguity because Y determines s=Y/4 uniquely. The calculation illustrates power maps of a reciprocal-coordinate hyperbola.
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