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Power maps of a reciprocal-coordinate hyperbola
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2021
/
Paper 1
/
11
/
c
/
Solution
2026-10-18
View more
From
X
=
s
2
−
4
and
Y
=
4
s
, elimination of
s
gives
Re
v
=
16
(
Im
v
)
2
−
4
,
−
15
≤
Im
v
≤
15.
(1)
This makes the
real part
a
quadratic function
of the
imaginary part
. There is no
sign
ambiguity
because
Y
determines
s
=
Y
/4
uniquely. The
calculation
illustrates
power maps of a reciprocal-coordinate hyperbola
.
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:
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