Product of exponentiable objects is exponentiable
= Product of exponentiable objects is exponentiable
If $A$ and $B$ are <exponentiable objects>, then
$$
-\times(A\times B)\cong(-\times A)\times B
$$
has the composite of their exponential functors as a right adjoint. The <terminal object> supplies the empty product, so exponentiable objects are closed under finite products.