The Kronecker–Weber theorem says that every finite abelian extension of is contained in a cyclotomic field. We prove its quadratic case by identifying the ramification that a quadratic number field must have.
For an odd prime , the cyclic Galois group of has exactly one subgroup of index two. Its fixed field is quadratic and is unramified at every finite prime other than . For a squarefree integer , the discriminant of is if , and otherwise. A nontrivial quadratic discriminant supported on the odd prime must therefore be
Indeed cannot give a nontrivial extension unramified at two, whereas exactly one of is congruent to one modulo four. Thus
This identifies the quadratic subfield of a prime cyclotomic field using ramification, without a Gaussian-sum computation.
Now let with squarefree. Multiply by . Every odd prime then occurs with even exponent, so its square class is represented by one of . Thus adjoining the square roots of the removes all possible odd-prime ramification; the remaining quadratic factor is contained in
The original is a rational multiple of a product of these square roots. It belongs to the compositum of and the prime cyclotomic fields just used. This compositum is itself contained in a cyclotomic field, proving the theorem for .
The sharper conductor statement follows from the same ramification calculation. For the fundamental discriminant of , put
The possibilities for follow immediately from the quadratic discriminant formula. The corresponding fields are trivial, , and , lying in the cyclotomic fields of conductors . Their conductors are coprime to the odd primes in the product. Hence quadratic Kronecker–Weber theorem by ramification gives the explicit conclusion