Quantum differential cross-section from a scattering amplitude
= Quantum differential cross-section from a scattering amplitude
If
$$
\psi\sim e^{ikz}+f(\theta)\frac{e^{ikr}}r,
$$
then the ratio of scattered radial <probability current> through $r^2d\Omega$ to the incident probability flux is
$$
\frac{d\sigma}{d\Omega}=|f(\theta)|^2.
$$