Reverse Loewner flow
= Reverse Loewner flow
{c}
For a continuous driver $U$ and terminal time $T$, the reverse Loewner flow solves
$$
\partial_sh_s(z)=-\frac2{h_s(z)-(U_{T-s}-U_T)},
\qquad h_0(z)=z.
$$
It satisfies $h_T(z)=g_T^{-1}(U_T+z)-U_T$.
= Reverse Loewner flow
{c}
For a continuous driver $U$ and terminal time $T$, the reverse Loewner flow solves
$$
\partial_sh_s(z)=-\frac2{h_s(z)-(U_{T-s}-U_T)},
\qquad h_0(z)=z.
$$
It satisfies $h_T(z)=g_T^{-1}(U_T+z)-U_T$.