Right-sign denominator correction in neutral-meson mixing
= Right-sign denominator correction in neutral-meson mixing
If a wrong-sign amplitude is $r e^{-i\delta}g_++g_-$, the same final state's right-sign amplitude is $g_++r e^{-i\delta}g_-$. Their ratio is not exactly obtained by replacing the right-sign rate with a pure exponential. For series $N=n_0+n_1t+n_2t^2$ and $D=1+d_1t+d_2t^2$, division gives $N/D=n_0+(n_1-n_0d_1)t+[n_2-n_1d_1+n_0(d_1^2-d_2)]t^2+O(t^3)$.