Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 73 4 i Solution Created 2026-10-03 Updated 2026-10-07
Use small Rossby number , slow evolution on the advective time scale, small interface displacements relative to each layer depth, shallow hydrostatic layers, stable reduced gravity , and inviscid unforced flow. On a beta plane, take of the same small order as the Rossby number. The internal Burger number is retained at order unity so stratification and relative-vorticity effects can both enter the leading potential-vorticity anomaly.
The rigid-lid pressure in two-layer flow comes from neglecting the free-surface volume displacement in the rigid-lid approximation; it does not permit setting the common horizontal pressure gradient to zero. The small surface displacement multiplied by retains a finite lid-pressure multiplier. Write , , and let denote this common pressure potential. Leading geostrophic balance giveswith at leading order. Literally setting to a spatial constant in the momentum gradients before taking the rigid-lid limit would suppress the upper-layer pressure field and fail to produce general two-layer QG dynamics.
Taking curl of each shallow-water momentum equation and using layer continuity gives material conservation of . Expanding it to first order and advecting the anomaly by the leading geostrophic velocity yieldsThe two-layer quasi-geostrophic potential vorticity equations areHere the common background has been removed and the anomaly multiplied by . The advection term is retained at the same slow order as the time derivative even though the leading velocity/pressure balance was linear geostrophy. On an plane simply set .