Rolling acceleration with rotational inertia
= Rolling acceleration with rotational inertia
For a round body with $I=\gamma Ma^2$ rolling without slipping down an incline, static friction gives
$$
a_{\rm cm}=\frac{g\sin\alpha}{1+\gamma}.
$$
= Rolling acceleration with rotational inertia
For a round body with $I=\gamma Ma^2$ rolling without slipping down an incline, static friction gives
$$
a_{\rm cm}=\frac{g\sin\alpha}{1+\gamma}.
$$