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First-year sea ice is ice that has formed since the preceding summer melt season and has not yet survived a summer. It is usually thinner than older ice, although deformation can create thick sea-ice pressure ridges in a young cover.

A sea-ice pressure ridge forms where horizontal convergence compresses sea ice. The initially thinner sheet or colliding ice floes fracture and ride over or under one another. Continued convergence piles broken blocks into an emergent sail and a submerged keel. The submerged volume is normally larger because buoyancy supports the pile. Pores and brine-filled gaps initially make the rubble unlike a solid intact sheet; refreezing can consolidate it.

A sea-ice shear ridge develops along a fracture where neighbouring ice moves tangentially in opposite directions or at different speeds. Rough edges interlock, crush and locally converge, producing chains of piled blocks along the shear boundary. Thus the large-scale strain is mainly shear, but the actual production of ridge rubble involves local compression. Pure sliding of perfectly smooth parallel surfaces need not create a ridge. Pressure ridging is driven by convergence; shear ridging is driven by relative tangential motion with local crushing and convergence.

Let $H$ denote a ridge's peak sea-ice draft, reserving $h$ for the draft at a randomly sampled position. In the exponential ridge-draft model, normalization by the line density $\mu$ givesThe mean peak sea-ice draft isConsequentlywith $h_m>h_0$, $b$ having dimensions inverse length and $B$ inverse length squared. The normalized peak probability density function is a shifted exponential distribution.

For the triangular argument, interpret the common ridge shape as geometrically similar triangles with common along-track slope $\tan \delta$ and variable peak height. Literal congruence would require identical sizes and could not coexist with an exponential peak-draft distribution. Each side of a triangle has $dx=|dh|/\tan \delta$. A ridge reaching draft $H\ge h$ therefore contributes $2\cot \delta dh$ of horizontal track in the interval $[h,h+dh]$. Summing this occupation length over all qualifying peaks proves the triangular ridge occupation identity:ThusThis is a tail relation for sampled draft occupation, not an instruction to normalize $n$ and $g$ identically. Below $h_0$, the ideal triangles contribute $2\mu \cot \delta$ rather than the same exponential; level ice and gaps contribute their own draft distributions. If triangular keels are referenced to a level-ice base, the vertical coordinate must be shifted consistently. We also require nonoverlapping occupation: arbitrary choices of $\mu$, mean draft and slope can otherwise demand more than the available track length.

Observed mean keel slopes are typically of order $20^{\circ }$–$30^{\circ }$, with broad individual variation rather than a single universal angle. Orientation matters: if a track crosses a straight ridge at angle $\psi$ to the crest, $\tan {\delta }_{\mathrm{track}}=\tan {\delta }_{\perp }|\sin \psi |$. The track slope can therefore approach zero at a grazing crossing. A sonar morphology study found location-dependent mean slopes about $22^{\circ }$–$27^{\circ }$ after correcting for ridge orientation.

Young sea-ice pressure ridges often have recognizably triangular sections with angular, porous rubble and comparatively continuous crests. Melting, refreezing and repeated cracking modify older ridges: their blocks can become rounded and consolidated, and their keel or crest can fragment into separated hummocks rather than retain one triangular shape. A pre-exam multibeam study found first-year sea ice ridge slopes averaging roughly $27^{\circ }$, while multi-year sea ice ridges often consisted of irregular separated smooth blocks. Multi-year sections can be broader or locally shallower, but age alone does not determine one slope angle. The constant-slope triangle is a useful statistical idealization, not a faithful shape for every old ridge.

Sea-ice draft is the depth of the ice underside below the local water surface. Total thickness also includes the part above the water. A sea-ice pressure ridge has a spatially variable draft, and its peak draft differs from its mean along a track.

The support is $x>\theta$ and the probability density function isThe change of variables $z=\log (x-\theta )$ proves normalization. The threshold $\theta$ is a lower endpoint, distinct from the log-mean $m$ and log-standard-deviation $\sigma$. In measured sea-ice pressure ridge spacings, finite ridge widths and detection rules can create such a lower endpoint.

For nonoverlapping triangular sea-ice pressure ridges with a common along-track side slope $\tan \delta$, a ridge whose peak exceeds $h$ contributes $2\cot \delta dh$ of track length in a draft interval $dh$. Summing over peaks proves the identity. Above the cutoff of an exponential ridge-draft model, $g(h)=A{e}^{-bh}$ with $A=2B/(b\tan \delta )$. This draft occupation is not the normalized peak probability density function; level ice and shallower parts supply the remaining probability.