Skew-symmetrized transport form (source code)

= Skew-symmetrized transport form

For a velocity field that need not be divergence free, the corrected transport
$$
\widetilde B(u,v)=(u\mathbin\cdot\nabla)v+\frac12(\nabla\mathbin\cdot u)v
$$
satisfies $\langle\widetilde B(u,v),w\rangle=-\langle\widetilde B(u,w),v\rangle$ and therefore preserves the quadratic energy cancellation.