Skew-symmetry of incompressible transport
= Skew-symmetry of incompressible transport
For a periodic or boundary-tangent <divergence-free vector field> $u$, <integration by parts> gives
$$
\int (u\mathbin\cdot\nabla f)g
=-\int (u\mathbin\cdot\nabla g)f.
$$
Consequently $\int(u\mathbin\cdot\nabla f)f=0$, the cancellation underlying many fluid <energy estimates>.