Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 1 2 c Solution Created 2026-10-03 Updated 2026-10-14
Let be a smooth vector in the product description of the algebraic contragredient representation. Its open stabilizer contains for some . For every , choose with . Invariance of at its th coordinate givesforcing . Hence a smooth functional has finite support, contained among .
Conversely a finitely supported family has indices bounded by some . Each inverse linear character has the same kernel as its original linear character, and all those kernels contain . Thus this subgroup fixes the family. The smooth dual is thereforeThis is the principle that conductors force finite support in a smooth dual. For instance a product vector with every coordinate nonzero is a perfectly valid algebraic functional on the original direct sum, but is not smooth.