Smooth non-displaceability from self-intersection
= Smooth non-displaceability from self-intersection
For a compact orientable Lagrangian $L$, the identification $NL\cong T^*L$ gives
$$
[L]\cdot[L]=\pm\langle e(TL),[L]\rangle=\pm\chi(L).
$$
If $\chi(L)\ne0$, no smoothly isotopic copy of $L$ can be disjoint from it.