Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 18 5 c Solution Created 2026-10-03 Updated 2026-10-06
Take the threshold in the stated spectral gap for powers of a positive line bundle. For and , it givesA harmonic form must therefore be zero. The Dolbeault Hodge decomposition and the Dolbeault theorem identify its zero harmonic space with . Hence . For the form spaces already vanish. The gap controls the lowest eigenvalue including zero, so it rules out harmonic forms rather than just controlling the positive spectrum.