Spin-one-half singlet state
= Spin-one-half singlet state
{title2=$|0,0\rangle$}
For two spin-one-half particles, the singlet is
$$
|0,0\rangle=\frac{|\uparrow\downarrow\rangle-|\downarrow\uparrow\rangle}{\sqrt2}.
$$
Every component of the total spin annihilates it, and $\mathbf S^2$ has eigenvalue zero.