Squeegee gap leakage flux
= Squeegee gap leakage flux
{title2=$J\simeq2\epsilon/3+2\epsilon^{5/2}\Delta p/(9\pi\sqrt{2\delta})$}
For a rounded blade with local <parabolic lubrication gap> $d=\epsilon+x^2/(2\delta)$, $\epsilon\ll\delta$, the <Couette-Poiseuille flow in a thin gap> yields a floor-driven flux $2\epsilon/3$ and pressure-driven leakage proportional to $\epsilon^{5/2}\Delta p/\sqrt\delta$. Positive $J$ is from the upstream pile towards the rear.