A uniform example is . It contains the final segment , a club set. Therefore belongs to the club filter. Every two club sets in a regular uncountable cardinal intersect: alternately choose larger points from each and take the countable supremum, which remains below and lies in both by closure. Hence every member of the club filter is a stationary set, so is stationary.
However, every finite ordinal belongs to , and their increasing supremum does not. Thus is not closed and is not a club set. This is a stationary nonclosed member of the club filter for every regular uncountable .