Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 11 1 b Solution Created 2026-10-03 Updated 2026-10-14
Write for the limiting spreading model norm. We show that deleting any one coefficient does not increase it; iteration then gives every finite suppression.
Fix an index , the coefficients, and a small . Choose a generation threshold so that all the relevant full and shortened combinations beyond it approximate their model norms within . Fix the indices before position beyond this threshold. Since is a weakly null sequence, the Mazur lemma gives a finite convex combinationwith every after the fixed prefix. Choose the remaining indices after . For every , the full ordered combination with in slot has norm at most . Averaging these combinations givesThe shortened combination has norm at most , and approximates its own model norm within . Letting provesfor every finite set . Thus the model is a suppression-unconditional basic sequence with constant one. The convex-combination argument allows the omitted coordinate to sit between two retained coordinates; simply letting a single omitted index tend to infinity with all others fixed would not respect their order.