Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 347 3 b Solution Created 2026-10-03 Updated 2026-10-05
Analyze a local temperature perturbation at fixed radius and fixed surface density of a disk . The thermal timescale of an accretion disk is shorter than its viscous timescale, so mass redistribution is negligible during the perturbation. Let be viscous heating and radiative cooling, measured consistently through one face or both faces, and define net cooling by . A temperature increase is unstable if it decreases net cooling.
With gas pressure dominant, vertical hydrostatic equilibrium and the ideal gas law giveFor the alpha disk prescription with temperature-independent , , and the Keplerian rotation heating law isOne must not hold the steady-state fixed while perturbing the temperature: the stress and heating respond through , even though is temporarily fixed.
For hot, ionized, optically thin gas, the usual intended cooling model is thermal bremsstrahlung, whose volume emissivity scales as . Integrated vertically,Thus , andA hotter annulus expands vertically, lowering its density enough to offset the direct increase in bremsstrahlung emission; viscous heating still rises.
For an optically thick medium with the Kramers opacity law, at fixed . Thermalized radiative diffusion givesIts falling opacity lets a hotter annulus radiate much more efficiently.
For an optically thick medium with dominant electron-scattering opacity, is nearly independent of temperature. Provided enough true absorption is present to thermalize the radiation,This conclusion differs from the thermal instability of a radiation-pressure-dominated alpha disk, where the heating has a different temperature dependence. The question explicitly excludes that pressure regime.
The first conclusion needs its cooling assumption stated. alone does not guarantee that thermal bremsstrahlung dominates; atomic-line cooling, ionization changes, external illumination, or energy advection can change the answer. For a general optically thin emissivity , the corresponding exponent isAccordingly, under the same fixed- alpha prescription,The unstable/stable/stable classification is the standard free-free/diffusion answer, rather than a universal result specified by temperature and optical depth alone.