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Ultrarelativistic limit of the boosted Schwarzschild metric away from the null plane
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Past exam of the mathematics course of the University of Cambridge
/
2018
/
ii
/
Paper 3
/
38E
/
c
/
Solution
Created
2026-09-24
Updated
2026-10-03
View more
Hold
p
=
mγ
fixed. At
a
point with
x
=
t
,
A
=
2
γ
γ
2
(
x
−
v
t
)
2
+
y
2
+
z
2
p
⟶
0
,
(1)
but
γ
2
A
⟶
2∣
x
−
t
∣
p
.
(2)
The small-
A
expansions are
f
(
A
)
=
1
+
4
A
+
O
(
A
2
)
,
g
(
A
)
=
8
A
+
O
(
A
2
)
.
(3)
Consequently, with
H
=
4
p
/∣
x
−
t
∣
, the
Ultrarelativistic limit of the boosted Schwarzschild metric away from the null plane
is
d
s
2
=
−
d
t
2
+
d
x
2
+
d
y
2
+
d
z
2
+
H
(
d
t
−
d
x
)
2
,
x
=
t
.
(4)
Equivalently,
g
tt
=
−
1
+
H
,
g
t
x
=
g
x
t
=
−
H
,
g
xx
=
1
+
H
,
g
yy
=
g
zz
=
1
,
(5)
with all other components zero.
Total
articles
:
1