Variance comparison for Poisson exposure estimators
= Variance comparison for Poisson exposure estimators
The two variances are
$$
\operatorname{var}(\widehat\theta_{LS})
=\frac{\theta S_3}{S_2^2},
\qquad
\operatorname{var}(\widehat\theta_{MLE})
=\frac\theta{S_1}.
$$
Since $S_2^2\leq S_1S_3$ by Cauchy-Schwarz, maximum likelihood has no larger variance, with equality when all positive exposures are equal.