Volterra operator
= Volterra operator
{c}
{title2=$(Af)(x)=\int_0^x f(t)\,dt$}
{wiki}
The Volterra integration operator on $L^2([0,1])$ is compact and injective, but its inverse is differentiation and is unbounded. Its singular values $2/((2n-1)\pi)$ tend to zero, making recovery of a function from noisy indefinite-integral data an ill-posed inverse problem.
= Volterra integration operator
{c}
{synonym}