Wald test
= Wald test
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= Wald statistic
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For an approximately normal estimator, the one-parameter Wald statistic
$$
Z=\frac{\widehat\theta-\theta_0}{\operatorname{se}(\widehat\theta)}
$$
is approximately standard normal under $H_0:\theta=\theta_0$. A two-sided test reports $2\Phi(-|Z|)$.