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The Weyl fields have odd Grassmann parity. With the given epsilon convention, write ${\chi }_{\alpha }=(a,b)$ and ${\psi }_{\alpha }=(c,d)$, where all four components anticommute. Raising an index gives ${\chi }^{\alpha }=(b,-a)$ and ${\psi }^{\alpha }=(d,-c)$. HenceThe minus sign from the antisymmetric epsilon tensor is canceled by exchanging the two Grassmann-odd components. Therefore the Weyl spinor bilinear exchange identity isFor commuting numerical spinors the exchange sign would instead be negative. The answer here uses fermionic Weyl fields, as appropriate to the supersymmetric model.