= Dirac Lagrangian
{c}
{{wiki=Lagrangian_(field_theory)#Dirac_Lagrangian}}
$$
\mathcal{L} = \bar \psi ( i \hbar c {\partial}\!\!\!/ - mc^2) \psi
$$
where:
* ${\partial}\!\!\!$: <Feynman slash notation>
* $\bar \psi$: <Dirac adjoint>
Remember that $\psi$ is a 4-vetor, gamma matrices are 4x4 matrices, so the whole thing comes down to a <dot product> of two 4-vectors, with a modified $\psi$ by matrix multiplication/derivatives, and the result is a scalar, as expected for a <Lagrangian>.
Like any other <Lagrangian>, you can then recover the <Dirac equation>, which is the corresponding <equations of motion>, by applying the <Euler-Lagrange equation> to the Lagrangian.
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