An irreducible plane cubic has at most one singular point
ID: an-irreducible-plane-cubic-has-at-most-one-singular-point
Two distinct singular points would impose at least two zeros each on the restriction of the cubic to their joining line. A nonzero homogeneous polynomial of degree three cannot have total zero multiplicity four, so that restriction vanishes identically. The line would be a component, contradicting the irreducible polynomial hypothesis. This argument works in every characteristic.
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