 Catalan power bound from abc

Put $M=x^p$ for positive bases $x,y\ge 2$. The coprime triple $(y^q,1,x^p)$ has radical at most $xy<M^{2/3}$. The abc conjecture with $ϵ=1/6$ gives $M\le C_{1/6}{M}^{7/9}$, proving the bound. Both bases and both exponents are then bounded, since $2^p\le M$ and $2^q\le M-1$. Unlike a homogeneous Fermat equation, no common-scaling ambiguity occurs.