 Continuous-wave nuclear magnetic resonance

For constant drive, set the three rotating frame derivatives to zero. Substitution first gives $u=\Delta T_{2}v$, then $w=M_0-{\omega }_1{T}_{1}v$, henceThe absorption is proportional to ${\omega }_{1}v$. With $s\ll 1$, its frequency dependence is a Cauchy distribution profile, often called a Lorentzian. With appreciable $s$, the response broadens and $w=M_0/(1+s)$ on resonance: nuclear magnetic resonance saturation limits the response. The short-pulse amplitude in the previous example is not a weak continuous drive; these are different operating regimes of the same equations.