 Elliptic crack pressure dipole

Subtracting the uniform-flow pressure $-\mu Ux/k$ leaves $(\mu Ua/k)\alpha e^{-\xi }\cos \eta /(1+\alpha )$. The coordinate map has $r\sim a{e}^{\xi }/2$, so $e^{-\xi }\sim a/(2r)$, giving the displayed dipole coefficient. The one-half is essential. In the perfect-conductor limit the independent expression $p=-(\mu U/k)\mathrm{Re}\sqrt{z^2-a^2}$ has the same far-field expansion.