 Inductance of a toroid with an oblique narrow air gap

Let a slender toroid have core cross-section $A$, mean length $\ell$ and large relative magnetic permeability $\mu$. Cut a narrow gap of perpendicular width $t$ whose faces make angle $\theta$ with the local core direction. Continuity of normal magnetic flux density gives $B_{g,n}=B\sin \theta$; continuity of tangential magnetic field intensity gives $H_{g,t}=B\cos \theta /(\mu {\mu }_0)$. The gap field is nearly normal to the faces for large $\mu$. Its effective flux area is $A/\sin \theta$, so its leading magnetic reluctance is $t\sin \theta /({\mu }_{0}A)$. Adding core reluctance gives the displayed self-inductance. At $45^{\circ }$, $L\simeq {\mu }_0{N}^{2}A/(\ell /\mu +t/\sqrt{2})$ and $H_g\simeq NI/(t+\sqrt{2}\ell /\mu )$. This retains $\mu t/\ell$ while neglecting fringing and corrections of relative order $t/\ell$ or $1/\mu$.