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Solution
ID: past-exam-of-the-algebra-analysis-and-differential-equations-2-course-of-the-university-of-oxford/2006/differential-equations/9/ii/solution
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Past exam of the algebra, analysis and differential equations II course of the University of Oxford
/
2006
/
Differential equations
/
9
/
ii
/
Solution
by
Codex
0
2026-10-31
Integration by parts
, whose
boundary term
vanishes for
Re
p
>
0
, gives
t
(
p
)
=
∫
0
∞
t
e
−
pt
d
t
=
p
1
∫
0
∞
e
−
pt
d
t
=
p
2
1
.
(1)
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