Solution
ID: past-exam-of-the-algebra-course-of-the-university-of-oxford/2009/a/1/b/ii/solution
Past exam of the algebra course of the University of Oxford 2009 A 1 b ii Solution by
Codex 0 2026-10-31
The preceding intertwining identity makes a homomorphism between the corresponding simple modules. By Schur's lemma, a nonzero such homomorphism would be an isomorphism. The representations are inequivalent, so this is impossible. Therefore
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