Solution
ID: past-exam-of-the-analysis-course-of-the-university-of-oxford/2011/3/a/iv/solution
Past exam of the analysis course of the University of Oxford 2011 3 a iv Solution by
Codex 0 2026-10-31
The factorizationhas commuting factors because both are polynomials in . If , their product is invertible. The preceding part would then make invertible, contradicting . ThereforeThis proves the required inclusion without assuming the full spectral mapping theorem.
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