Solution

ID: past-exam-of-the-analytic-topology-and-axiomatic-set-theory-course-of-the-university-of-oxford/2009/b/6/iii/b/solution

Equality with the union is expressed by
The first conjunct says that every member of lies in some member of ; the second gives the reverse inclusion. Every quantifier is bounded by a parameter or by an element of a previously bounded parameter. Therefore bounded absoluteness applies, proving full absoluteness and hence upward absoluteness of . This only compares the relation for existing parameters; it does not require either class to contain the union of every one of its sets.

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