 Solution

Six inward-directed donor orbitals form symmetry-adapted linear combinations of $a_{1g}+e_g+t_{1u}$ symmetry. They mix respectively with metal $4s$, $(3d_{z^2},3d_{x^2-y^2})$ and $4p$ orbitals. Thus the sigma framework contains six occupied bonding molecular orbitals and six corresponding antibonding molecular orbitals. The metal $(d_{xy},d_{xz},d_{yz})$ orbitals have no sigma-compatible partner and remain nonbonding $t_{2g}$ orbitals in this model. The important metal-dominated octahedral splitting isThe $e_g^{\ast }$ orbitals point directly toward the donors; the $t_{2g}$ orbitals point between them. The original diagram shows the entire sigma framework, rather than treating the five metal d levels as the whole molecular-orbital diagram.

For the same donor set and approximately the same geometry, ${\Delta }_o(\mathrm{C}{\mathrm{o}}^{\mathrm{III}})>{\Delta }_o(\mathrm{C}{\mathrm{o}}^{\mathrm{II}})$. The higher metal charge usually shortens the metal–donor distances and strengthens the interaction that raises $e_g^{\ast }$. This comparison holds other chemical variables fixed: changing the ligand at the same time could reverse a comparison between two unrelated complexes.