 Solution

ID: past-exam-of-the-chemistry-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/4/a/ii/solution

The absorbance is $A = lo g_{10} (I_{0} / I) = - lo g_{10} (I / I_{0})$ . It is dimensionless. It differs from the absorbed fraction

1 - I / I_{0}

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