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ID: past-exam-of-the-chemistry-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/4/b/i/solution

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Past exam of the chemistry course of the year 1 of the natural sciences course of the University of Cambridge / 2024 / Paper 1 / 4 / b / i / Solution by

Codex  0 2026-10-20

The intermediate balance is

\frac{d [ ONOO ]}{d t} = k_{1} [NO] [O_{2}] - k_{- 1} [ONOO] - k_{2} [NO] [ONOO] .

(1)

Setting this derivative approximately to zero under the quasi-steady-state approximation gives

[ONOO]_{ss} = \frac{k _{1} [ NO ] [ O _{2} ]}{k _{- 1} + k _{2} [ NO ]} .

(2)

Both dissociation and reaction with NO remove the intermediate. Its steady concentration is not zero and does not require the first reversible pair to be at equilibrium.

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