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ID: past-exam-of-the-chemistry-course-of-the-year-3-of-the-natural-sciences-course-of-the-university-of-cambridge/2021/paper-2a/section-a/16/c/solution

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Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge / 2021 / Paper 2A / Section A / 16 / c / Solution by

Codex  0 2026-10-20

The descending line is $^{3} T_{1 g} (F)$ ; the low rising line is $^{3} T_{2 g}$ ; the steep line is $^{3} A_{2 g}$ ; and the branch starting at $15 B$ is $^{3} T_{1 g} (P)$ . Their high-field slopes, in the same order, are

- \frac{4}{5}, \frac{1}{5}, \frac{6}{5}, \frac{1}{5} .

(1)

These are slopes of the supplied absolute term energies relative to their chosen reference, not slopes of transition energies measured upward from the ground state. The two

T_{1 g}

states share a symmetry and mix, whereas the crossing of

A_{2 g}

and the upper

T_{1 g}

branch is allowed because they have different irreducible representations.

Figure 1.
Triplet crystal-field energies and their strong-field slopes
. **Details**.

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