Solution
ID: past-exam-of-the-chemistry-course-of-the-year-3-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-4/56/c/solution
Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge 2022 Paper 4 56 c Solution by
Codex 0 2026-10-20
This is a thermal Claisen rearrangement followed by intramolecular acetal exchange. Identify the six-atom array as the cyclopentenone enol-ether C=C–O–CH–C=C unit. In its concerted rearrangement:
- The O–CH bond breaks.
- A new C-C bond joins the other end of the cyclopentenone enol double bond to the cyclohexene carbon bearing CH(OEt).
- The former ether-bearing cyclopentene carbon becomes a ketone, and the cyclohexene double bond becomes the exocyclic methylene.
The intermediate is thus a substituted cyclopentane-1,3-dione, with the acetal tether now correctly placed for six-membered-ring closure. Its enol oxygen attacks the acetal carbon, replacing OEt and releasing ethanol. Enolization gives the conjugated cyclic enol ether drawn in the product; the second ethoxy group remains.
A chair-like Claisen rearrangement transition structure with the phenyl-bearing part of the cyclohexane directed outward avoids severe axial crowding. Suprafacial bond formation and the pre-existing configuration give the two indicated ring-junction hydrogens on opposite faces: the left H is a wedge and the right H a dash in the supplied orientation. Closure favors the acetal epimer with outward OEt, drawn as a wedge, while the original Ph remains dashed. This is substrate-controlled diastereoselection followed by conformationally selective acetal closure, rather than independent arbitrary assignment of three centres.
New to topics? Read the docs here!