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ID: past-exam-of-the-chemistry-course-of-the-year-3-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-4/64/a/solution

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Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge / 2022 / Paper 4 / 64 / a / Solution by

Codex  0 2026-10-20

For cubes of side

ℓ

, total area divided by total mass is

S = 6/ (ρ ℓ)

, independently of how many cubes share the

100 g

sample. With

S = 5000 m^{2} k g^{- 1}

and

ρ = 2330 kg m^{- 3}

ℓ = \frac{6}{ρS} = 5.15 \times 1 0^{- 7} m .

(1)

This assumes accessible external faces, negligible contact-area losses and equally sized nonporous cubes; BET adsorption can also count accessible internal surface in a porous powder.

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