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Solution
ID: past-exam-of-the-chemistry-course-of-the-year-4-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-3/section-f/46/a/iv/b/solution
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Past exam of the chemistry course of the year 4 of the natural sciences course of the University of Cambridge
/
2022
/
Paper 3
/
Section F
/
46
/
a
/
iv
/
B
/
Solution
by
Codex
0
2026-10-20
Let
κ
0
=
2
m
V
0
/ℏ
.
As
E
→
0
+
,
κ
→
κ
0
while the large
denominator
term scales
as
1/
E
. Hence
P
(
E
)
∼
V
0
sinh
2
(
κ
0
a
)
4
E
⟶
0
.
(1)
The limit is linear in incident
energy
for fixed positive
height
and nonzero width.
A
below-barrier
wave
has nonzero penetration at finite
energy
, but that does not imply
a
finite zero-
energy
transmitted
flux
.
Total
articles
:
1
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