 Solution

There is exactly one such nontrivial game for every $n\ge 1$: the unanimity game requiring every player. PutIt is a simple cooperative game, and permuting players preserves every coalition value. Thus it has the required symmetry of players in a cooperative game. It is also a convex cooperative game: if both $S,T$ are winning, all four terms in the supermodular inequality have value $1$; if exactly one is winning, their union is $N$ and their intersection loses, giving equality $1=1$; if neither wins, the right-hand side is zero and the inequality follows from nonnegativity. For $n=1$ the same definition gives the sole player value $1$.

To prove uniqueness, first establish that convex simple games are unanimity games. If $S,T$ are winning coalitions, the supermodular inequality givesso their intersection is also winning. The family of winning coalitions is finite and nonempty. Its intersection $K$ is therefore winning and nonempty, since the empty coalition loses. Every winning coalition contains $K$, and monotonicity makes every superset of $K$ winning. Hence $v=u_K$.

If $K$ were a proper nonempty subset of $N$, take $i\in K$ and $j\notin K$, and let $T=N\setminus \{i,j\}$. Then $T\cup \{i\}=N\setminus \{j\}$ contains $K$ and wins, whereas $T\cup \{j\}=N\setminus \{i\}$ loses. This violates symmetry of players in a cooperative game, which requires those two coalition values to agree. Thus $K=N$, proving the claimed count. The “nontrivial” convention excludes the identically zero game; if that degenerate game were also called simple, it would supply one additional symmetric convex example.