Solution
ID: past-exam-of-the-differential-equations-1-course-of-the-university-of-oxford/2017/2/b/i/solution
Past exam of the differential equations 1 course of the University of Oxford 2017 2 b i Solution by
Codex 0 2026-10-31
Where , . By the mean value theorem, the solution is strictly decreasing on every interval where it avoids . At , the derivative is zero, so a constant segment there is possible. Thus all solutions are nonincreasing, while strict decrease need not persist through an interval spent at that equilibrium.
New to topics? Read the docs here!