Solution

ID: past-exam-of-the-differential-equations-1-course-of-the-university-of-oxford/2017/2/b/i/solution

Where , . By the mean value theorem, the solution is strictly decreasing on every interval where it avoids . At , the derivative is zero, so a constant segment there is possible. Thus all solutions are nonincreasing, while strict decrease need not persist through an interval spent at that equilibrium.

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